Calculate the uncertainty in velocity of an electron. If the uncertainty in its position `10^(-13)c.m.` `(h=6.6xx10^(-34)J,m=9.1 xx 10^(-31)kg)`
A. `5.79 xx 10^(8)m//sec`.
B. `5.79 xx 10^(13)m//sec`.
C. `5.79 xx 10^(10)m//sec`.
D. `5.79 xx 10^(6)m//sec`.

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Correct Answer - A
`A(g)+e^(-)rarrA^(-)(g)" "DeltaH=-a(E.G.E.)`
`A^(-)(g)rarrA(g) +e^(-)" "DeltaH=+b(l.E)`

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