Four numbers are in A.P. If their sum is 20 and the sum of their squares is 120, then the middle terms are
A. 2, 4
B. 4, 6
C. 6, 8
D. 8, 10

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1 Answers

Correct Answer - B
Let the number are `a - 3d, a - d, a + d, a + 3d`
given, `a - 3d + a - d + a + d + a + 3d = 20 " " rArr 4a = 20 rArr a = 5`
and `(a - 3d)^(2) + (a - d)^(2) + (a + d)^(2) + (a + 3d)^(2) = 120 rArr 4a^(2) + 20d^(2) = 120`
`rArr 4 xx 5^(2) + 20 d^(2) = 120 " " rArr d^(2) = 1 rArr d = -+ 1`
Hence number 2,4,6,8 or 8,6,4,2

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