A particle is moing with a velocity of `10m//s` towards east. After 10s its velocity changes to `10m//s` towards north. Its average acceleration is:-
A particle is moing with a velocity of `10m//s` towards east. After 10s its velocity changes to `10m//s` towards north. Its average acceleration is:-
A. zero
B. `sqrt(2) m//s^(2)` towards N-W
C. `(2)/sqrt(2) m//s^(2)` towards N-W
D. `(1)/sqrt(2)m//s^(2)` towards N-W
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Correct Answer - B
Acceleration `veca=(Deltavecv)/(Deltat)=(10hatj-10hati)/(10)`
`=-hati+hatj` (west north)
`|veca|=sqrt(1+1)=sqrt(2)` (north-west)
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