In the previous question, the mean velocity of the rocket reaching the maximum height is :
In the previous question, the mean velocity of the rocket reaching the maximum height is :
A. `100ms^(-1)`
B. `50ms^(-1)`
C. `500ms^(-1)`
D. `25//3ms^(-1)`
4 views
1 Answers
Correct Answer - C
`"Mean velocity"=("Displacement")/("Total time")=("Total height")/("Total time")`
`=(10,000m)/(20sec)=500 m//s`
4 views
Answered