When 1 mole gas is heated at constant volume, temperature is raised from 298 to 308 K. Heat supplied to the gas in 500 J. Then, which statement is correct ?
A. `q=W=500 J , DeltaE=0`
B. `q=DeltaE=500 Jm W=0`
C. `q=-W=500 J, DeltaE=0`
D. `DeltaE=0,q=W=-500 J`

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1 Answers

Correct Answer - B
We know that , `DeltaH=DeltaE+pDeltaV`
When, `DeltaV=0`
`therefore DeltaH=DeltaE`
In given problem `DeltaH=500 J `
`-W=-pDeltaV,DeltaV=0`
So, `DeltaE=q=500 J`

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