The side of a square is increasing at ther rate of `0.2 cm//s`. The rate of increase of perimeter w.r.t. time is :

Question

The side of a square is increasing at ther rate of `0.2 cm//s`. The rate of increase of perimeter w.r.t. time is :

The side of a square is increasing at ther rate of `0.2 cm//s`. The rate of increase of perimeter w.r.t. time is :
A. 0.2 cm/s
B. 0.4 cm/s
C. 0.6 cm/s
D. 0.8 cm/s

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
If side=a then rate of increase of perimeter w.r.t. time `-4((da)/(dt))-4(0.2)=0.8cm//s`

4 views Answered 2023-02-05 15:29