A solution of colourless salt `H` on boiling with excess `NaOH` produces a nonflammable gas.The gas evolution ceases after some time.Upon addition of

Question

A solution of colourless salt `H` on boiling with excess `NaOH` produces a nonflammable gas.The gas evolution ceases after some time.Upon addition of

A solution of colourless salt `H` on boiling with excess `NaOH` produces a nonflammable gas.The gas evolution ceases after some time.Upon addition of `Zn` dust to the same solution, the gas evolution restarts.The colourless salt(s) `H` is (are) :
A. `NH_(4)NO_(3)`
B. `NH_(4)NO_(2)`
C. `NH_(4)Cl`
D. `(NH_(4))_(2)SO_(4)`

Monjur Alahi

6 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Correct Answer - A,B
All ammonium salts on reaction with alkali produce ammonia.The nitrate and nitrite also on reduction with nascent hydrogen (produced by the reaction of zinc and sodium hydroxide) produce the ammonia gas according to the following reactions.
`NH_(4)NO_(2)+NaOH to NaNO_(2)+NH_(3)+H_(2)O`
`NH_(4)NO_(2)+NaOH to NaNO_(3)+NH_(3)+H_(2)O`
`NaNO_(2)+6[H]overset(Zn//NaOH) to NaOH+NH_(3)+H_(2)O`
`NaNO_(3)+8[H]overset(Zn//NaOH) to NaOH+NH_(3)+2H_(2)O`
So options `(A)` and `(B)` are correct.