The correct sequence which shows decreasing order of the ionic radii of the elements is
A. `AI^(3+) gt Mg^(2+) gt Na^(+) gt F^(-) gt O^(2-)`
B. `Na^(+) gt Mg^(2+) gt AI^(3-) gt O^(2-) gt F`
C. `Na^(+) gt F^(-) gt Mg^(2+) gt O^(2-) gt AI^(3+)`
D. `O^(2-) gt F^(-) gt Na^(-) gt Mg^(2+) gt AI^(3-)`

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1 Answers

Correct Answer - D
For isoelectronic species, ionic radii `prop (1)/("nuclear charge")`.
So, correct order of ionic radii is `._(8)O^(2-) gt _(9)F^(-) gt _(11)Na^(+) gt _(12)Mg^(2+) gt _(13)AI^(3+)`

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