The decreasing order of bond angles from `NH_(3) (107^(@))` to `SbH_(3)(91.3^(@))` down the group 15 elements is due to :
The decreasing order of bond angles from `NH_(3) (107^(@))` to `SbH_(3)(91.3^(@))` down the group 15 elements is due to :
A. increasing bond pair : bond pair repulsion
B. increasing p-orbital character on `sp^(3)` orbital
C. decreasing lone pair- bond pair repulsion
D. decreasing electronegativity.
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Correct Answer - B
Due to increasing size of central atom, s character in `sp^(3)` hybridisation decreases and corresponding p character increases.
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