Given the order of density: Diamond`gt`Graphite`gt`Fullerence `C_(60)`, choose thye correct order for `C-C` bond length (Consider large bond length if

Question

Given the order of density: Diamond`gt`Graphite`gt`Fullerence `C_(60)`, choose thye correct order for `C-C` bond length (Consider large bond length if

Given the order of density:
Diamond`gt`Graphite`gt`Fullerence `C_(60)`, choose thye correct order for `C-C` bond length (Consider large bond length if there are two different bondlengths)
A. Diamond `lt` graphite`lt` fullerene `(C_(60))`
B. Diamond `gt` graphite`gt` fullerene `(C_(60))`
C. Diamond `gt` fullerene `(C_(90^(@))) gt`graphite
D. Diamond `lt` fullerene `(C_(90^(@))) lt`graphite

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Correct Answer - C
Diamond -`sp^(3)` , no `pi`-bond character and `C-C` bond length=`154` pm
graphite -`sp^(2)`, aromatic and `pi` electrons are delocalised and `C-C` bond length =`141.5` pm
fullerene-`sp^(2)`, not so good delocalisation and there are two types of bond length. `C-C` bond length decreases as compared with diamond but is more than of graphite. Bond lengths are `143.5` pm and `138.3` pm.