Which of the following is the correct order of decreasing `S_(N^2)` reactivity?

Question

Which of the following is the correct order of decreasing `S_(N^2)` reactivity?

Which of the following is the correct order of decreasing `S_(N^2)` reactivity?
A. `RCH_(2) X gt R_(3) CX gt R_(2)CHX`
B. `RCH_(2)XgtR_(2)CHXgt R_(3)RX`
C. `R_(3)CX gt R_(2)CHX gt R_(2)CHX gt RCH_(2)X`
D. `R_(2)CHX gt R_(2)CX gt RCH_(2)X`.

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
It is the correct decreasing order of reactivity (i.e., `1^(@) gt 2^(@) gt 3^(@)`) towards `S_(N^(2))` reaction mechanism. Since steric hindrance which the attacking nuleophile is expected to experience decreases in this order

5 views Answered 2023-02-05 15:29