`~(pvvq)vv(~p^^q)` is equivalent to
`~(pvvq)vv(~p^^q)` is equivalent to
A. q
B. p
C. `~p`
D. `~q`
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Correct Answer - C
`~(pvvq) vv(~p^^q)`
`-=(~p^^~q) vv(~p^^q)~`
`-=~p^^(~p^^q)`
`-=~p^^(~qvvq)`
`-=~p^^t`
`-=~p`
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Answered