The resistance of a decinormal solution of an electrolyte in a conductivity cell was found to be 245 `Omega`. Calculate the equivalent conductance of

Question

The resistance of a decinormal solution of an electrolyte in a conductivity cell was found to be 245 `Omega`. Calculate the equivalent conductance of

The resistance of a decinormal solution of an electrolyte in a conductivity cell was found to be 245 `Omega`. Calculate the equivalent conductance of the solution if the electrodes in the cell were 2 cm part and each had an area of 3.5 sq. cm.

Monjur Alahi

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2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Correct Answer - `23.32Omega^(-1)cm^(2)(g. eq.)^(-1)`
Step I. Calculation of specific conductnce (k)
Cell constant`=l//a=((2" cm"))/((3.5" cm"^(2)))=0.5714" cm"^(-1)`
Specific conductance(k)`=("Cell constant")/("Resistance")=((0.5714 cm^(-1)))/((245" ohm"))=2.332xx10^(-3)" ohm^(-1) cm^(-1)`.
Step II. Calculation of equivalent conductance`(Lambda_(E))`
`Lambda_(E)=(kxx1000)/(C)=((2.48xx10^(-3)ohm^(-1)cm^(-1))xx(1000" cm"^(3)))/(0.1("g eq"))`
`=23.32" ohm"^(-1) cm^(2)("g eq")^(-1)`.