At `25^(@)C`, the resistance of `0.01 N NaCl` solution is `200 ohm` . If cell constant of the conductivity cell is unity, then the equivalent conducta

Question

At `25^(@)C`, the resistance of `0.01 N NaCl` solution is `200 ohm` . If cell constant of the conductivity cell is unity, then the equivalent conducta

At `25^(@)C`, the resistance of `0.01 N NaCl` solution is `200 ohm` . If cell constant of the conductivity cell is unity, then the equivalent conductance of the solution is:

Monjur Alahi

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2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Correct Answer - `500 ohm^(-1)`
Step I. Calculation of specific conductance
Specific conductance (k)`=("cell constant")/("R")=((1" cm"^(-1)))/((200 ohm))=0.005" ohm"^(-1) cm^(-1)`.
Step II. Calculation of equivalent conductance of solution
`Lambda_(E)=(1000xxk)/(N)=((1000 cm^(3))xx(0.005" ohm"^(-1)cm^(-1)))/((0.01"g eq"))=500" ohm"^(-1)cm^(2)("g eq")^(-1)`.