`(~(pvvq))vv(~p^^q)` is logically equivalent to
`(~(pvvq))vv(~p^^q)` is logically equivalent to
A. p
B. `~p`
C. q
D. `~q`
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Correct Answer - B
`(~(pvvq))vv(~p^^q)`
`-=(~p^^~q)vv(~p^^q)`
`-=~p^^(~qvvq)`
`-=~p`
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