A proton describes a circle of radius `1 cm` in a magnetic field of strength `0.10 T`.What would be the radius of the circle described by an deuteron

Question

A proton describes a circle of radius `1 cm` in a magnetic field of strength `0.10 T`.What would be the radius of the circle described by an deuteron

A proton describes a circle of radius `1 cm` in a magnetic field of strength `0.10 T`.What would be the radius of the circle described by an deuteron moving with the same speed in the same meagnetic field?

Monjur Alahi

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2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B::C
`r=(mv)/(qB) rArr (m/q)_(D)=2(m/q)_(P)rArrr_(D)=2r_(P)=2cm`

5 views Answered 2023-02-05 15:29