A proton is projected with a velocity of `3xx10^(6) m//s` perpendicular to a uniform magnetic field of `0.6 T`.Find the acceleration of the proton.mass of proton`=5/3xx10^(-27) kg`

6 views

1 Answers

Correct Answer - A::B::D
`f=qVB rArra=f/m=(qVB)/m=864/5xx10^(12) m//s^(2)`

6 views

Related Questions