A bar magnet suspended freely in a uniform magnetic field is vibrating with a time period of 3s. If the field strength is increased to 4 times of the
A bar magnet suspended freely in a uniform magnetic field is vibrating with a time period of 3s. If the field strength is increased to 4 times of the earlier field strength, then the time period (in second) will be
A. 12
B. 6
C. 1.5
D. 0.75
4 views
1 Answers
As, the time period,= T=2pi`sqrt((1)/(MB))`
` " " T alpha (1)/(sqrtB) Rightarrow (T_(2))/(T_(1))=sqrt(B_(1)/(B_(2))`
` " " T_(2)/(3)=sqrt((1)/(4)) or T_(2)=1.5s.`
4 views
Answered