At T (K) , if the rate constant of a first order reaction is `4.606xx10^(-3)s^(-1)`, the time to reduce the initial concentration of the reactant to `

Question

At T (K) , if the rate constant of a first order reaction is `4.606xx10^(-3)s^(-1)`, the time to reduce the initial concentration of the reactant to `

At T (K) , if the rate constant of a first order reaction is `4.606xx10^(-3)s^(-1)`, the time to reduce the initial concentration of the reactant to `(1)/(10)` in seconds is :
A. 500
B. 1000
C. 100
D. 50

Monjur Alahi

6 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

For first order reaction :
`k=(2.303)/(t)log.([R_(0)])/([R_(t)])`
`4.606xx10^(-3)=(2.303)/(t)log.((1)/(1//10))`
`t=(2.303)/(4.606xx10^(-3))=500 sec`

6 views Answered 2023-02-05 15:29