For the first order reaction, the rate constant is `4.62 xx 10^(-2)s^(-1)`. What will be the time required for the initial concentration `1.5` mol of

Question

For the first order reaction, the rate constant is `4.62 xx 10^(-2)s^(-1)`. What will be the time required for the initial concentration `1.5` mol of

For the first order reaction, the rate constant is `4.62 xx 10^(-2)s^(-1)`. What will be the time required for the initial concentration `1.5` mol of the reactant to be be reduced to 0.75 mol?

Monjur Alahi

7 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

According to available data:
`[A]_(0) =1.5 mol, [A]=0.75 mol, k=4.62 xx 10^(-2)s^(-1)`.
`t=(2.303)/(k) log ([A]_(0))/([A]) = (2.303)/(4.62 xx 10^(-2)s^(-1)) = 15s`

7 views Answered 2023-02-05 15:29