The rate constant of the first order, decomposition of `N_(2)O_(5)` at `25^(@)` is `3.00 xx 10^(-3) min^(-1)`. If the initial concentration of `N_(2)O
The rate constant of the first order, decomposition of `N_(2)O_(5)` at `25^(@)` is `3.00 xx 10^(-3) min^(-1)`. If the initial concentration of `N_(2)O_(2)` is `2.00 xx 10^(-3)` mol `L^(-1)`, How long will it take for the concentration to drop to `5.00 xx 10^(-4)` mol `L^(-1)`?
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According to available data:
`a=2.0 xx 10^(-3) mol L^(-1), (a-x) = 5.0 xx 10^(-4) mol L^(-1), k=3.0 xx 10^(-3) min^(-1)`
`t=(2.303)/k log a/(a-x) = (2.303)/(3 xx 10^(-3) min^(-1)) = 4.62 xx 10^(2)` min
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