1 mL of methyl acetate was added to a flash containing 20 mL of N/20 HCl maintained at `[email protected]`. 2mL of the reaction mixture were withdrawn at different
1 mL of methyl acetate was added to a flash containing 20 mL of N/20 HCl maintained at `[email protected]`. 2mL of the reaction mixture were withdrawn at different intervals and titrate with a standard alkali solution. The following results were obtained :
`{:("Time (min)",0,75,119,183,oo),("Alkali used (mL)",19.24,24.20,26.60,29.32,42.03):}`
show that the reaction follows first order kinetics
1 Answers
In case, the hydrolysis follows first order kinetics, then
`k=(2.303)/(t)log_(10).([A]_(0))/([A])=(2.3030)/(t)log_(10).(V_(oo)-V_(0))/(V_(oo)-V_(t))`
When `t=75 "min", V_(oo)=42.03, V_(0)=19.24,V_(t)=24.20`
`K=(2.303)/(75)log_(10).((42.03-19.24))/((42.03-24.20))=(2.303)/(75)log_(10).(22.79)/(17.83)`
`=0.00327 "min"^(-1)`
`t=119 "min"^(-1), V(oo)=42.03,V_(0)=19.24,V_(t)=26.60`
`K=(2.303)/(75)log_(10).((42.03-19.24))/((42.03-26.60))`
`=(2.303)/(119)log_(10).(22.79)/(15.43)`
`0.00327 "min"^(-1)`
Since, the values of k are constant, hence, it follows first order kinetics.