Calculate the standard internal energy of formation of liquid methyl acetate `(CH_(3)COOCH_(3))` from its standard enthalpy of foramtion, which is `-44.291 kJ "mole"^(-1)` at `25^(@)C`
A. `-433`
B. `+433`
C. `-452.82`
D. `452.82`

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1 Answers

Correct Answer - A
`3C_((s))+3H_(2(g))+O_(2(g))rarrCH_(3)COOCH_(3)(l)DeltaH_(f)^(0)= -442.91`
`Delta U=DeltaH-Delta n_(g)RT`
`=(-442.91-(-4)xx8.314xx(298)/(1000))kJ "mole"^(-1)`
`= -433 kJ"mole"^(-1)`

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