Calculate the mass of `Hg_(2)Cl_(2)` which can be propared by the reduction of mercury (II) ions in the presence of chloride ions by the passage of 5.

Question

Calculate the mass of `Hg_(2)Cl_(2)` which can be propared by the reduction of mercury (II) ions in the presence of chloride ions by the passage of 5.

Calculate the mass of `Hg_(2)Cl_(2)` which can be propared by the reduction of mercury (II) ions in the presence of chloride ions by the passage of 5.0 ampere current for 3.0 hours.

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

Related Questions

The rate of reaction: `2NO + Cl_(2) rarr 2NOCl` is given by the rate, equation rate `= k[NO]_(2)[Cl_(2)]`. The value of the rate constant can be incre

2 Answers 5 Views

Assertion : Mercuric chloride becomes red on adding KI solution. Reason : Mercuric chloride undergoes hydrolysis forming basic chloride.

2 Answers 5 Views

Calculate the mass of mercury which can be liberated from `HgO` at `25^(@)C` by the treatment of excess HgO with 41.84 kJ of heat at : (a) constant pr

2 Answers 4 Views

Calculate `DeltaS_(r)^(@)` at 298 K of , (i) `Na(s) +(1)/(2)CL_(2)(g) to NaCl(s)`, (ii) `(1)/(2) N_(2)(s) + 2H _(2)(g) +(1)/(2) Cl_(2)(g) to NH_(4) Cl

2 Answers 9 Views

Statement-1:Sodium chloride is added during electrolysis of fused anhydrous magnesium chloride. Statement-2:Anhydrous magnesium chloride is obtained b

2 Answers 5 Views

Calculate the standard potential for the reaction, `Hg_(2)Cl_(2)+Cl_(2) rarr 2Hg^(2+)+4Cl^(-)` Given : `{:(Hg_(2)Cl_(2)+2e^(-) rarr 2Hg+2Cl^(-),,E^(@)

2 Answers 4 Views

What happens when `Mn(II)` ions free from chloride ions react with acidified solution of `(NH_(4))_(2)S_(2)O_(8)` or `K_(2)S_(2)O_(8)` in presence of

2 Answers 5 Views

An aqueous solution contains `Hg^(2+),Hg_(2)^(2+),Pb^(2+),Ag^(+),Bi_(3+)` and `Cd^(2+)`.Out of these, how many ions will produce white precipitate wit

2 Answers 4 Views

The overall reaction electrochemical cell at 298K. `Ag(s)|AgI(s)|I^(-)(aq)||Cl^(-)(aq)|Hg_(2)Cl_(2)|Hg(l)|Pt(s)` [Given: `E_(Cl^(-)|Hg_(2)Cl_(2)|Hg)^(

2 Answers 4 Views

Given : `Hg_(2)^(2+) rightarrow 2Hg`, `E^(@) = 0.789 V` and `Hg^(2+) + 2e^(-) rightarrow Hg`, `E^(@) = 0.854V` Calculate the equilibrium consant for `

2 Answers 5 Views

Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - 132.34 g
`2Hg^(2+)+2Cl^(-)+underset(2 F)(2e^(-)) rarr underset("1 mole")(Hg_(2)Cl_(2))`

5 views Answered 2023-02-05 15:29