An aqueous solution contains `Hg^(2+),Hg_(2)^(2+),Pb^(2+),Ag^(+),Bi_(3+)` and `Cd^(2+)`.Out of these, how many ions will produce white precipitate wit

Question

An aqueous solution contains `Hg^(2+),Hg_(2)^(2+),Pb^(2+),Ag^(+),Bi_(3+)` and `Cd^(2+)`.Out of these, how many ions will produce white precipitate wit

An aqueous solution contains `Hg^(2+),Hg_(2)^(2+),Pb^(2+),Ag^(+),Bi_(3+)` and `Cd^(2+)`.Out of these, how many ions will produce white precipitate with dilule `HCl` ?

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Correct Answer - 3
`Pb^(2+) + 2Cl^(-) to PbCl_(2) darr ("white") , Hg_(2)^(2+) + 2Cl^(-) to Hg_(2)Cl_(2) darr` (white)
`Ag^(+) + Cl^(-) to AgCl darr` (white)
`K_(sp)` of chlorides of `Pb^(2+)` and `Hg_(2)^(2+)` is low as compared to `K_(sp)` of `Hg^(2+)` and `Cd^(2+)`. Chloride ion concentration provided by dilute `HCl` is just enough to exceed the `K_(sp)` of `PbCl_(2)` and `Hg_(2)Cl_(2)`. Thus `Pb^(2+)` and `Hg_(2)^(2+)` are precipitated as their chlorides.