When an alternating voltage E = Eosin ωt is applied to circuit, a current I = Iosin (ωt+π/2) flows through it. The average power dissipated in the circuit is :

(a) Erms.Irms

(b) EoIo

(c) \(\frac{E_oI_o}{\sqrt2}\) 

(d) Zero

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Option : (d) Zero

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