A transistor is operated in common emitter configuration at `V_C=2 V`. Such that a change in the base current from `100 muA` to `200 muA` produces a c

Question

A transistor is operated in common emitter configuration at `V_C=2 V`. Such that a change in the base current from `100 muA` to `200 muA` produces a c

A transistor is operated in common emitter configuration at `V_C=2 V`. Such that a change in the base current from `100 muA` to `200 muA` produces a change in the collector current of 5mA to 10 mA. The current gain is
A. 100
B. 150
C. 75
D. 50

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

Related Questions

The current amplification factor `alpha` of a common base transistor and the current amplification factor `beta`of a common emitter transistor are not

2 Answers 5 Views

A transistor has a current amplification factor (current gain) of 50. In a common emitter amplifier circuit, the collector resistance is chosen as `5O

2 Answers 4 Views

In n-p-n transistor circuit, the collector current is `10 mA`. If `90%` of the holes reach the collector, find emitter and base currents.

2 Answers 4 Views

The current gain for a common emitter amplifier is 69. If the emitter current is 7 mA, the base current is

2 Answers 5 Views

In a common -emitter transistor amplifier, an increase of `50muA` in the base current causes an increase of `1.0mA` in the collector current . Calcula

2 Answers 4 Views

For a common emitter transistor amplifier, the audio signal voltage across the collector resistance of `2 kOmega` is 2 V. Suppose the current amplific

2 Answers 4 Views

The ac current gain of a transistor is 120. What is the change in the collector current in the transistor whose base current changes by `100 muA`?

2 Answers 5 Views

The input resistance of a transistor is `1000 Omega` on charging its base current by `10 muA`, the collector current increases by 2 mA. If a load resi

2 Answers 4 Views

Assertion : In a transistor the base is made thin. Reason: A thin base makes the transistor stable.

2 Answers 4 Views

Prove that `^100 C_2^(100)C_2+^(100)C_2^(100)C_4+^(100)C_4^(100)C_6++^(100)C_(98)^(100)C_(100)=1/2[^(200)C_(98)-^(100)C_(49)]dot`

2 Answers 5 Views

Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
Current gain, `beta=(DeltaI_C)/(DeltaI_B)=((10-5)xx10^(-3))/((200-100)xx10^(-6))=50`

4 views Answered 2023-02-05 15:29