The internal energy of a gas is given by `U= 5 + 2PV`. It expands from `V_(0)` to `2V_(0)` against a constant pressure `P_(0)`. The heat absorbed by t

Question

The internal energy of a gas is given by `U= 5 + 2PV`. It expands from `V_(0)` to `2V_(0)` against a constant pressure `P_(0)`. The heat absorbed by t

The internal energy of a gas is given by `U= 5 + 2PV`. It expands from `V_(0)` to `2V_(0)` against a constant pressure `P_(0)`. The heat absorbed by the gas in the process is :-
A. `-3P_(0)V_(0)`
B. `3P_(0)V_(0)`
C. `2P_(0)V_(0)`
D. `P_(0)V_(0)`

Monjur Alahi

7 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
`DeltaU = 2P_(0) DeltaV` & `W = P_(0)DeltaV`
So `Q = W + DeltaU = 3P_(0)DeltaV = 3P_(0)V_(0)`

7 views Answered 2023-02-05 15:29