`2CaSO_4 (s) hArr 2CaO(s)+2SO_(2)(g)+O_2(g), DeltaHgt0` Above equilibrium is establised by taking some amount of `CaSO_4(s)` in a closed container at

Question

`2CaSO_4 (s) hArr 2CaO(s)+2SO_(2)(g)+O_2(g), DeltaHgt0` Above equilibrium is establised by taking some amount of `CaSO_4(s)` in a closed container at

`2CaSO_4 (s) hArr 2CaO(s)+2SO_(2)(g)+O_2(g), DeltaHgt0`
Above equilibrium is establised by taking some amount of `CaSO_4(s)` in a closed container at 1600 K. Then which of the following may be correct options ?
A. Moles of CaO(s) will increase with the increase in temperature
B. if the volume of the container is doubled at equilibrium then partial pressure of `SO_2(g)` will change at new equilibrium
C. If the volume of the container is halved partial pressure of `O_2`(g) at new equilibrium will remain same
D. If two moles of the He gas is added at constant pressure then the moles of CaO(s) will increase

Monjur Alahi

6 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Correct Answer - A,C,D
(A)As reaction is endothermic therefore with increases in temperature it will go in the forward direction hence moles of CaO will increases.
(B)With the increase of decrease of volume partial pressure of the gases will remain same.
(C )Due to the addition of inert gases at constant pressure reaction will proceed in the direct in which more number of gaseous moles are formed.