30 ml of 0.06 M solution of the protonated form of an anion of acid methonine `(H_2A^(+))` is treated with 0.09 M NaOH. Calculate pH after addition of 20 ml of base `pKa_1=2.28 and pKa_2=9.2`
A. 5.5
B. 5.74
C. 9.5
D. None

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1 Answers

Correct Answer - B
`pH=(pK_(a_1)+pK_(a_2))/2 =(2.28+9.2)/2=5.74`

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