The ratio of the sums of m arithmatic means and n arithmetic means between two numbers is 

A) n : m 

B) 2m – 1 : 2n – 1 

C) m : n 

D) 2m + 1, 2n + 1

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2 Answers

Correct option is (C) m : n

Sum of m arithmatic means between a and b

\(=(a+d)+(a+2d)+.......+(a+md)\)

\(=ma+d\,(1+2+.....+m)\)

\(=ma+d\,\frac{m(m+1)}2\)

\(=ma+\frac{m(m+1)}2\times\frac{b-a}{m+1}\)     \((\because d=\frac{b-a}{m+1})\)

\(=ma+\frac{m}2\,(b-a)\)

\(=\frac{2am+mb-ma}2\)

\(=\frac{m(a+b)}2\)

\(\therefore\) Sum of n arithmatic means between a and b \(=\frac{n(a+b)}2\)

\(\therefore\) Required ratio \(=\cfrac{\frac{m(a+b)}2}{\frac{n(a+b)}2}\)

\(=\frac ma=m:n\)

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Correct option is C) m : n

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