Coefficients of variation of two distributions are 50 and 60, and their arithmetic means are 30 and 25, respectively. Difference of their standard dev
Coefficients of variation of two distributions are 50 and 60, and their arithmetic means are 30 and 25, respectively. Difference of their standard deviations is
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Correct Answer - A
Here, `(CV)_(1)=50,(CV)_(2)=60,overline(x_(1))=30 " and" overline(x_(2))=25`
` therefore (CV)_(1)=(sigma_(1))/(overline(x_(1)))xx100`
`implies 50=(sigma_(1))/(30)xx100`
`therefore sigma_(1)=(30xx50)/(100)=15`
and `CV_(2)=(sigma_(2))/(overline(x_(2)))xx100`
`implies 60=(sigma_(2))/(25)xx100`
`therefore sigma_(2)=(60xx25)/(100)=15`
Now, `sigma_(1)-sigma_(2)=15-15=0`
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