de-Broglie wavelength of an electron in the nth Bohr orbit is `lambda_(n)` and the angular momentum is `J_(n)` then

Question

de-Broglie wavelength of an electron in the nth Bohr orbit is `lambda_(n)` and the angular momentum is `J_(n)` then

de-Broglie wavelength of an electron in the nth Bohr orbit is `lambda_(n)` and the angular momentum is `J_(n)` then
A. `J_(n)proplambda_(n)`
B. `lambda_(n)prop(1)/(J_(n))`
C. `lambda_(n)propJ_(n)^(2)`
D. None of these

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - A
`lambda (h)/(p)=(h)/(mv)`
or `" " lambda prop (1)/(v)`
`:. " " lambda_(n)prop n rArr J_(n)=n(h)/(2pi) i.e., J_(n) prop n`
Hence, `" " lambda_(n)propJ_(n)`

5 views Answered 2023-02-05 15:29