The de Broglie wavelength of an electron moving in a circular orbit is `lambda` . The minimum radius of orbit is :

Question

The de Broglie wavelength of an electron moving in a circular orbit is `lambda` . The minimum radius of orbit is :

The de Broglie wavelength of an electron moving in a circular orbit is `lambda` . The minimum radius of orbit is :
A. `lambda/pi`
B. `lambda/(2pi)`
C. `lambda/(4pi)`
D. `lambda/(3pi)`

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

Related Questions

An electron having kinetic energy T is moving in a circular orbit of radius R prependicular to a uniform magnetic field induction `barB` . If kinetic

2 Answers 5 Views

de-Broglie wavelength of an electron in the nth Bohr orbit is `lambda_(n)` and the angular momentum is `J_(n)` then

2 Answers 5 Views

Assertion Second orbit circumference of hydrogen atom is two times the de-Broglie wavelength of electrons in that orbit Reason de-Broglie wavelength o

2 Answers 7 Views

if an electron is revolving in its bohr orbit having bohr radius of `0.529Å`, then the radius of third orbit is

2 Answers 8 Views

When light of wavelength `lambda` is incident on a metal surface, stopping potential is found to be x. When light of wavelength n`lambda` is incident

2 Answers 8 Views

If `[(lambda^(2)-2lambda+1,lambda-2),(1-lambda^(2)+3lambda,1-lambda^(2))]=Alambda^(2)+Blambda+C`, where A, B and C are matrices then find matrices B a

2 Answers 6 Views

The circumference of circular orbit of electron in a `He^(+)` ion is five times the de-Broglie wavelength associated with the electron. Find the radiu

2 Answers 11 Views

If the equations `4x^(2)-x-1=0` and `3x^(2)+(lambda+mu)x+lambda-mu=0` have a root common, then the rational values of `lambda` and `mu` are

2 Answers 5 Views

Find all values of `lambda` for which the `(lambda-1)x+(3lambda+1)y+2lambdaz=0(lambda-1)x+(4lambda-2)y+(lambda+3)z=0 2x+(3lambda+1)y+3(lambda-1)z=0` p

2 Answers 5 Views

Calculate the de Broglie wavelength associated with the following : (i) electrons moving with a speed of `10^(5)ms^(-1)` (ii) protons moving with a sp

2 Answers 10 Views

Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
We know `2 pir=nlambda`
For minimum radius `n=1`
`2pir_("min")=lambda`
`r_("min")=lambda/(2pi)`

5 views Answered 2023-02-05 15:29