A 0.004 M solution of `Na_(2)SO_(4)` is isotonic with a 0.01 M solution of glucose at the same temperature. The apparent degree of dissocia-tion of `N

Question

A 0.004 M solution of `Na_(2)SO_(4)` is isotonic with a 0.01 M solution of glucose at the same temperature. The apparent degree of dissocia-tion of `N

A 0.004 M solution of `Na_(2)SO_(4)` is isotonic with a 0.01 M solution of glucose at the same temperature. The apparent degree of dissocia-tion of `Na_(2)SO_(4)` is :
A. `25%`
B. `50%`
C. `75%`
D. `85%`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - c
Since the solutions are isotonic, They have the same osmotic pressure also.
`pi_(Na_(2)SO_(4))=pi_("glucose")`
`ixx0.004 RT = 0.01 RT`
`i=0.01/0.004=2.5`
`Na_(2)SO_(4)hArr2Na^(+)+SO_(4)^(2-)`
`alpha=(i-1)/(n-1)=(2.5-1)/(3-1)=1.5/2`
=0.75 or 75%

4 views Answered 2023-02-05 15:29