The vapour pressure of acetone at `20^(@)C` is 185 torr. When 1.2 g of a non-volatile substance was dissolved in 100 g of acetone at `20^(@)C`, its va

Question

The vapour pressure of acetone at `20^(@)C` is 185 torr. When 1.2 g of a non-volatile substance was dissolved in 100 g of acetone at `20^(@)C`, its va

The vapour pressure of acetone at `20^(@)C` is 185 torr. When 1.2 g of a non-volatile substance was dissolved in 100 g of acetone at `20^(@)C`, its vapour pressure was 183 torr. The molar mass of the substance is :
A. 128
B. 488
C. 32
D. 64

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - d
`(P_(A)^(@)P_(S))/P_(S)=(W_(B)xxW_(A))/(W_(A)xxM_(B))`
`((185-183))/((183))=((1.2 g)xx(58 g mol^(-1)))/((100g)xxM_(B))`
`M_(B)=((1.2g)xx(58g mol^(-1))xx(183))/(2xx(100g))=63.68g mol^(-1)`
=64 g `mol^(-1)`

5 views Answered 2023-02-05 15:29