The moleality of NaOH solution formed by dissolving 4 g of it in 250 mL water is :

The moleality of NaOH solution formed by dissolving 4 g of it in 250 mL water is :
A. 0.4 m
B. 0.8m
C. 0.2m
D. 0.1 M Glucose.

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

Salim Ahmed Kawsar

Correct Answer - a
Molality (m)
`=("Mass of mass//Molar mass")/("Mass of solvent in kg")`
`=((4g)//(40g mol^(-1)))/(250//(1000kg))=0.4 m`
It is assumed that density of water is `1g//mL`.

5 views Answered 2023-02-05 15:29

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