The molal freezing point for water is `1.86^(@)C//m`. Therefore. The freezing point of 0.1 m NaCI solution in water is expected to be:

Question

The molal freezing point for water is `1.86^(@)C//m`. Therefore. The freezing point of 0.1 m NaCI solution in water is expected to be:

The molal freezing point for water is `1.86^(@)C//m`. Therefore. The freezing point of 0.1 m NaCI solution in water is expected to be:
A. `-1.86^(@)C`
B. `-0.186^(@)C`
C. `-0.372^(@)C`
D. `+0.372^(@)C`

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - c
`DeltaT_(f)=iK_(f)m=2xx1.86^(@)C//mxx0.1m`
`=0.372^(@)C`
`F.P.=0-0.372^(@)C=-0.372^(@)C`

5 views Answered 2023-02-05 15:29