Equimolar aqueous solutions of NaCI and `BACI_(2)` are prepared. If the freezing point of NaCI is `-2^(@)C`, the freezing point of `BaCI_(2)` solution

Question

Equimolar aqueous solutions of NaCI and `BACI_(2)` are prepared. If the freezing point of NaCI is `-2^(@)C`, the freezing point of `BaCI_(2)` solution

Equimolar aqueous solutions of NaCI and `BACI_(2)` are prepared. If the freezing point of NaCI is `-2^(@)C`, the freezing point of `BaCI_(2)` solution is expected to be:
A. `-2^(@)C`
B. `-3^(@)C`
C. `-1.5^(@)C`
D. `-1.66^(@)C`

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - b
`DeltaT_(f)("Colligative property")` in linked with number of particles or ions in solution
`NaCItoNa_((aq))^(+)+CI_((aq))^(-)`
` BaCI_(2)toBa_((aq))^(2+)+2CI_((aq))^(-)`
`"If "alph a"for " NaCI is -2^(@)C`
`"Then " alpha "for" BaCI_(2) "is expected to be" =-3^(@)C.`

5 views Answered 2023-02-05 15:29