An aqueous solution freezes at-`0.186^(@)C(K_(f)=1.86,K_(b)=0.512)`. What is the elecation in boiling point ?

An aqueous solution freezes at-`0.186^(@)C(K_(f)=1.86,K_(b)=0.512)`. What is the elecation in boiling point ?
A. 0.186
B. 0.512
C. 0.86
D. 0.0512.

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

Salim Ahmed Kawsar

Correct Answer - d
For the same solution
`(DeltaT_(b))/K_(b)=(DeltaT_(b))/K_(f)`
of `DeltaT_(b)=(DeltaT_(f))/(T_(f))xxK_(b)`
`=((0.186^(@)C))/1.86xx0.512.`
=`0.0512^(@)C`

4 views Answered 2023-02-05 15:29

Related Questions

Molality of an aqueous solution that produce an elevation of boiling point of 1.00 K at 1 atm pressure. `K_(b)` for water is `0.512 K kg mol^(-1)`

2 Answers 5 Views

An aqueus solution freezes at 272.07 K while pure water freezes at 273 K. Determine the molality and boiling point of the solution. Given `K_(f)=1.86

2 Answers 8 Views

Why does a solution containing a non-volatile solute have higher boiling point than the pure solvent? Why is elevation in boiling point a colligative

2 Answers 5 Views

An aqueous solution containing urea found to have boiling point more than the normal boiling point of water (373.13 K). When the same solution was coo

2 Answers 16 Views

Calculate the molecular mass of a substance, 1.0 gram of which when dissolved in 100 gram of solvent gace an elecation of 0.307 K in the boiling point

2 Answers 10 Views

Calculate boiling point of a solution pepared by dissoving 15.0 g of NaCI in 250.0 g of water (`K_(b)` for water = 0.512 K kg `mol^(-1)`), Molar mass

2 Answers 4 Views

Calculate the boiling point elevation for a solution prepared by adding 10 g of `CaCI_(2)` to 200 g of water. (`K_(b)` for water = 0.512 K kg mol, Mol

2 Answers 5 Views

KBr is 80% dissociated in aqueous solution of 0.5 m concentration (Given `K_(f)=1.86 " K kg" mol^(-1))`. The solution freezes at :

2 Answers 4 Views

pure benzene freezes at `5.3^(@)C`. A solution of 0.233 g of phenyl acetic acid `(C_(6)H_(5)CH_(2)COOH)` freezes at `4.47^(@)C`. Form this observation

2 Answers 8 Views

Freezing point of an aqueous solution is `(-0.186)^(@)C`. Elevation of boiling point of the same solution is `K_(b)=0.512^(@)C`, `K_(f)=1.86^(@)C`. Fi

2 Answers 6 Views

এক্সাম দিয়ে মেধা যাচাই করুন

Job Preparation (1125)

Admission (754)

এসএসসি (10)

এইচএসসি (5)