`0.1 M NaOH (aq)` solution having density `1.2 gm//ml` will have molality
A. `0.2 M`
B. `0.15 M`
C. `0.08 M`
D. `0.12 M`

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1 Answers

Correct Answer - C
`(d)/(M) = (1)/(m) + (MM)/(1000)`
`(1.2)/(0.1) = (1)/(m) + (40)/(1000)`
`m = 0.08 m`

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