Methane ( Considered to be an ideal gas ) initially at `25^(@)C` and 1 bar pressure is heated at constant
pressure until the volume has dobbled . The variation of the molar heat capacity with absolute temperature
is given by `C_(P)=20 + 0.001 T`
where `C_(P)` is in `JK^(-1) mol^(-1)` . Calculate molar (a) `DeltaH`(b) `DeltaU`.

4 views

1 Answers

Correct Answer - (a) `DeltaH= 6.093 kJ mol^(-1)`. (b) `DeltaU= 3.616 kJ mol^(-1)`.
`DeltaH= overset(2xx298) underset(298)int C_(P)dT= overset(2xx298)underset(298)int(20 +0.001)TdT`
`= 6093.206J`
`DeltaH= DeltaU +nRTDeltaT`
`DeltaU= 3.616 KJ "mol"^(-1)`

4 views

Related Questions