When two mole of an ideal gas `(C_(p.m) = (5)/(2)R)` heated from `300 K` to `600 K` at constant pressure. The change in entropy of gas `(DeltaS)` is:

Question

When two mole of an ideal gas `(C_(p.m) = (5)/(2)R)` heated from `300 K` to `600 K` at constant pressure. The change in entropy of gas `(DeltaS)` is:

When two mole of an ideal gas `(C_(p.m) = (5)/(2)R)` heated from `300 K` to `600 K` at constant pressure. The change in entropy of gas `(DeltaS)` is:
A. `(3)/(2)" R " " In " 2`
B. `-(3)/(2)" R In " 2`
C. `5 "R In" 2`
D. `(5)/(2) "R In" 2`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
`DeltaS = nC_(p.m) "In" (T_(2))/(T_(1)) = 2 xx (5)/(2)"R In" (600)/(300) = 5"R In 2`

4 views Answered 2023-02-05 15:29