The efficiency of a carnot cycle is `1//6` . On decreasing the tempertaure of the sink by `65^(@)C`, the efficiency increases to `1//3` .Calculate the

Question

The efficiency of a carnot cycle is `1//6` . On decreasing the tempertaure of the sink by `65^(@)C`, the efficiency increases to `1//3` .Calculate the

The efficiency of a carnot cycle is `1//6` . On decreasing the tempertaure of the sink by `65^(@)C`, the efficiency increases to `1//3` .Calculate the tempretaure of source and sink .

Monjur Alahi

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2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - `117^(@)C, 52^(@)`
`(1)/(6)=1 - (T_(L))/(T_(H))`
`T_(H)=(6)/(5)T_(L)`
`(1)/(3)= 1-((T_(L) - 65))/(T_(H))`
`T_(L) = 325 K = 52 ^(@)C`

4 views Answered 2023-02-05 15:29