A reversible heat engine A(based on carnot cycle ) absorbs heat from a reservoir at 1000 K and rejects heat to a reservoir at `T_(2)`. A second revers

Question

A reversible heat engine A(based on carnot cycle ) absorbs heat from a reservoir at 1000 K and rejects heat to a reservoir at `T_(2)`. A second revers

A reversible heat engine A(based on carnot cycle ) absorbs heat from a reservoir at 1000 K and rejects
heat to a reservoir at `T_(2)`. A second reversible engine B absorbs, the same amount of heat as rejected by
the engine A, from the reservoir at `T_(2)` and rejects energy to a reservoir at 360 K.
If the efficienices of engines A and B are the same then the temperature `T_(2)` is .
A. 680 K
B. 640 K
C. 600 K
D. none

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
For heat engines A: `eta= (1000- T_(2))/(1000) rArreta_(B) = (T_(2) - 360)/(T_(2))`
`eta_(A) = eta_(B)`
`So(1000-T_(2))/(1000)=(T_(2) - 360)/(T_(2)) = T_(2) = sqrt(360 xx 1000)=600 K`

5 views Answered 2023-02-05 15:29