Consider the reaction at 300 K `H_(2)(g)+Cl_(2)(g) to 2HCl(g)" "DeltaH = - 185 kJ//mol` Calculate `DeltaU` if 3 mole of `H_(2)` completely react with
Consider the reaction at 300 K
`H_(2)(g)+Cl_(2)(g) to 2HCl(g)" "DeltaH = - 185 kJ//mol`
Calculate `DeltaU` if 3 mole of `H_(2)` completely react with 3 mo,le f of `Cl_(2)` to from HCl.
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Correct Answer - D
`Deltan_(g) = 0 rArr DeltaH= DeltaU = - 185 kJ//"Mole"`
For three moles = - `185 xx 3 = - 555 `
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