From the following data at `25^(@)C`, Calculate the standard enthalpy of formation of `FeO(s)` and of `Fe_(2)O_(3) (s)`.
`{:(,"Reaction",Delta_(r)H^(@)" (kJ/mole)"),((1),Fe_(2)O_(3)(s)+3C ("graphite") rarr 2Fe(s) +3CO(g),492.6),((2),FeO(s)+C("graphite") rarr Fe(s)+CO(g),155.8),((3),C("graphite")+O_(2) (g) rarr CO_(2)(g),-393.51),((4),CO(g)+1//2O_(2)(g) rarr CO_(2)(g),-282.98):}`

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Correct Answer - `-266.3` kJ/mol and `-824.2` kJ/mol
(i) `Fe+1/2 O_(2) rarr FeO`
`DeltaH=-155.8-393.51+282.98=-266.3" kJ mol"^(-1)`
(ii) `2Fe+3CO rarr Fe_(2)O_(3)+3C`
`DeltaH=-492.6+848.94-1180.53=824.19" kJ mol"^(-1)`

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