For the reaction `N_(2)(g) +3H_(2)(g) to 2NH_(3)(g)` If `Delta[NH_(3)]//Deltat= 4 xx 10^(-8)mol L^(-1)s^(-1)`, what is the value of `Delta[H_(2)]//Del

Question

For the reaction `N_(2)(g) +3H_(2)(g) to 2NH_(3)(g)` If `Delta[NH_(3)]//Deltat= 4 xx 10^(-8)mol L^(-1)s^(-1)`, what is the value of `Delta[H_(2)]//Del

For the reaction
`N_(2)(g) +3H_(2)(g) to 2NH_(3)(g)`
If `Delta[NH_(3)]//Deltat= 4 xx 10^(-8)mol L^(-1)s^(-1)`, what is the value of `Delta[H_(2)]//Deltat`=?

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

Related Questions

The enthalpy of formation of ammonia is `-46.0 KJ mol^(-1)` . The enthalpy change for the reaction `2NH_(3)(g)rarr N_(2)(g)+3H_(2)(g)` is :

2 Answers 8 Views

The value of `DeltaH-DeltaE` for the following reaction at `27^(@)C` will be `2NH_(3)(g)toN_(2)(g)+3H_(2)(g)`

2 Answers 5 Views

For a reaction, `2NH_(3)(g) overset("Pt") to N_(2)(g) + 3H_(2)(g)` (Rate =k) i) Write the order and molecularity of reaction is two. II) Unit of k =`m

2 Answers 5 Views

For the reaction `N_(2) + 3H_(2) to 2NH_(3)` if `(Delta[NH_(3)])/(Deltat) = 2 xx 10^(-4) mol L^(-1)s^(-1)`, the value of `(-Delta[H_(2)])/(Deltat)` wo

2 Answers 5 Views

Calculate the order of reaction for the reaction `2NH_(3)(g) to N_(2)(g) + 3H_(2)(g)` Given that half life period `(t_(1//2))` under a pressure of 50m

2 Answers 5 Views

`Ag^(+) + NH_(3) ltimplies [Ag(NH_(3))]^(+), k_(1)=6.8 xx 10^(-5)` `[Ag(NH_(3))]^(+) + NH_(3) ltimplies [Ag(NH_(3))_(2)]^(+)`, `k_(2) = 1.6xx10^(-3)`

2 Answers 8 Views

Given : (i) `NH_(3) (g) + 3Cl_(2)(g) rarr NCl_(3)(g)+3HCl(g)`, `Delta H_(1)` (ii) `N_(2)(g) + 3H_(2)(g) rarr 2NH_(3)(g)` , `Delta H_(2)` (iii) `H_(2)(

2 Answers 5 Views

What is `Delta_(r)G`(KJ/mol) for sysnthesis of ammonia at 298K at following sets of partial pressure: `N_(2)(g) + 3H_(2)(g) hArr 2NH_(3) , Delta_(r) G

2 Answers 9 Views

Ammonia gas can be prepared by following reaction : `CaO (s) + 2NH_(4) Cl (s) rarr 2NH_(3) (g) + H_(2)O (g) + CaCl_(2) (s)` If 112 gm of CaO and 224 g

2 Answers 4 Views

Calculate the order of reaction form the following data: `2NH_(3) rarr N_(2) + 3H_(2)` (reaction) `|{:("Pressure (mm Hg)",50,100,200),("Half lives (mi

2 Answers 6 Views

Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Rate of reaction = `(-d[N_(2)])/(dt) = -1/3 (d[H_(2)])/(dt) = 1/2(d[NH_(3)])/(dt)`
`(d[H_(2)])/(dt) = -(3d)/2[NH_(3)]/(dt)`
`=-3/2(d[NH_(3)])/(dt) = -3/2 xx (4 xx 10^(-4) mol L^(-1)s^(-1))`
`-6 xx 10^(-4)mol L^(-1)s^(-)`.

5 views Answered 2023-02-05 15:29