The value of `DeltaH-DeltaE` for the following reaction at `27^(@)C` will be `2NH_(3)(g)toN_(2)(g)+3H_(2)(g)`
The value of `DeltaH-DeltaE` for the following reaction at `27^(@)C` will be
`2NH_(3)(g)toN_(2)(g)+3H_(2)(g)`
A. `8.314xx27xx(-2)`
B. `8.314xx300xx(-2)`
C. `8.314xx27xx(-2)`
D. `8.314xx273xx(1)`
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Correct Answer - D
`DeltaH=DeltaE+Deltan_(g)RT`
`:. DeltaH-DeltaE=Deltan_(g)RT`
`2NH_(3)(g)toN_(2)(g)+3H_(2)(g)`
Here `Deltan_(g)=(3+1)-2=4-2=2`
`R=8.314 JK^(-1)mol^(-1)`
`T=27+273=300 K`
`:. DeltaH-DeltaE=Deltan_(g)RT=(2)xx(8.314)xx(300)`
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