What will happen to the value of emf of the following cell if the cencentration of the electrolyte in the anode compartment is increased ?
`Zn | Zn^(2+)(0.1 M)||Cu^(2+)(0.1 M) Cu`.

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1 Answers

According to Nernst equation
`E_(cell)=E_(cell)^(@)-(0.0591)/(2)"log"([Zn^(2+)])/([Cu^(2+)]`
If the concentration of the `Zn^(2+)` is increased, emf of the cell will decrease.

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